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\(F = ma\) - AMAZONAWS
\(F = ma\) - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 \boxed{11.2 \, \text{cm}}
📌 Substituting the given radius, \(A = 3.14 \times 7^2 = 3.14 \times 49 = 153.86 \, \text{cm}^2\).
📌 \[ R'(x) = \frac{d}{dx}[\ln(x^2 + 4x + 5)] = \frac{2x + 4}{x^2 + 4x + 5} \]
📌 Solution: Using $\tan(60^\circ) = \frac{\text{height}}{\text{shadow length}}$, we substitute $\tan(60^\circ) = \sqrt{3}$ and shadow length $5\,\text{cm}$. Solving for height: $\text{height} = 5 \cdot \sqrt{3}$. Thus, $\boxed{5\sqrt{3}}$.
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