\[ R'(x) = \fracddx[\ln(x^2 + 4x + 5)] = \frac2x + 4x^2 + 4x + 5 \] - AMAZONAWS 📅 March 11, 2026 👤 scraface Mar 11, 2026
![\[ R'(x) = \frac{d}{dx}[\ln(x^2 + 4x + 5)] = \frac{2x + 4}{x^2 + 4x + 5} \]](https://soloferat.biz.id/images/-rx--fracddxlnx2--4x--5--frac2x--4x2--4x--5-.jpg)
