C''(2) = e^-2(5(2)^2 - 20(2) + 10) = e^-2(20 - 40 + 10) = e^-2(-10) < 0 \quad ( extlocal maximum). - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$C''(2) = e^{-2}(5(2)^2 - 20(2) + 10) = e^{-2}(20 - 40 + 10) = e^{-2}(-10) < 0 \quad ( ext{local maximum}).$