[(x - 4)^2 - (x - 1)^2] + [(y - 5)^2 - (y - 2)^2] + [(z - 6)^2 - (z - 3)^2] = 0 - AMAZONAWS 📅 March 11, 2026 👤 scraface Mar 11, 2026
![[(x - 4)^2 - (x - 1)^2] + [(y - 5)^2 - (y - 2)^2] + [(z - 6)^2 - (z - 3)^2] = 0](https://soloferat.biz.id/images/x---42---x---12--y---52---y---22--z---62---z---32--0.jpg)
