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Home » Now, compute \( \sqrt-2i \). Let \( \sqrt-2i = a + bi \), then: - AMAZONAWS

Now, compute \( \sqrt-2i \). Let \( \sqrt-2i = a + bi \), then: - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$Now, compute \( \sqrt{-2i} \). Let \( \sqrt{-2i} = a + bi \), then:$

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