But since 506 ≠ 0, no solution has $y = 0$ (would require $m = n$, $m^2 = 506$, not square), so all solutions come in pairs $(x,y)$ and $(x,-y)$, except if $y = 0$, which doesn’t occur. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$But since 506 ≠ 0, no solution has $y = 0$ (would require $m = n$, $m^2 = 506$, not square), so all solutions come in pairs $(x,y)$ and $(x,-y)$, except if $y = 0$, which doesn’t occur.$

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