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\[ x = \fracv_0^2 \sin(2\theta)2g. \] - AMAZONAWS
\[ x = \fracv_0^2 \sin(2\theta)2g. \] - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 Solution: The prime factorization of 2048 is $2^{11}$, and 1024 is $2^{10}$. The LCM of two numbers is the product of the highest powers of all primes present. Thus, $ ext{LCM}(2048, 1024) = 2^{11} = 2048$. The answer is $oxed{2048}$.
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![\[ x = \frac{v_0^2 \sin(2\theta)}{2g}. \]](https://soloferat.biz.id/images/-x--fracv02-sin2theta2g-.jpg)
