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Home » \[ h(t) = h_0 - rt^2. \] - AMAZONAWS

\[ h(t) = h_0 - rt^2. \] - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$h(t) = h_0 - rt^2.$

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P(X=9) = C(10,9) (0.8)^9 (0.2)^1 = 10 × 0.134217728 × 0.2 ≈ 0.268435
So the square roots are \( 1 - i \) and \( -1 + i \)
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