\[ (1 + i)^2 = 1 + 2i + i^2 = 1 + 2i - 1 = 2i \] - AMAZONAWS 📅 March 11, 2026 👤 scraface Mar 11, 2026
![\[ (1 + i)^2 = 1 + 2i + i^2 = 1 + 2i - 1 = 2i \]](https://soloferat.biz.id/images/-1--i2--1--2i--i2--1--2i---1--2i-.jpg)
