t = \frac{\ln\left(\frac32\right)}{\ln\left(\frac1.051.03\right)} \approx \frac0.40550.0198 \approx 20.48 - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$t = \frac{\ln\left(\frac{3}{2}\right)}{\ln\left(\frac{1.05}{1.03}\right)} \approx \frac{0.4055}{0.0198} \approx 20.48$