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Home » Let \(r = \sqrtx^2 + y^2 = c \sin^2\phi\) - AMAZONAWS

Let \(r = \sqrtx^2 + y^2 = c \sin^2\phi\) - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
Let \(r = \sqrt{x^2 + y^2} = c \sin^2\phi\)

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