To maximize \( d \), we take the largest divisor of 144 such that \( \frac144d \geq 2 \) and there exist coprime \( m, n \) with \( m + n = \frac144d \). - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$To maximize \( d \), we take the largest divisor of 144 such that \( \frac{144}{d} \geq 2 \) and there exist coprime \( m, n \) with \( m + n = \frac{144}{d} \).$