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Home » This is valid because \(a = 1012\), \(b = 1012\), and \(\gcd(1012, 1012) = 1012\). Therefore, the maximum possible value is \(\boxed1012\). - AMAZONAWS

This is valid because \(a = 1012\), \(b = 1012\), and \(\gcd(1012, 1012) = 1012\). Therefore, the maximum possible value is \(\boxed1012\). - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
This is valid because \(a = 1012\), \(b = 1012\), and \(\gcd(1012, 1012) = 1012\). Therefore, the maximum possible value is \(\boxed{1012}\).

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📌 Using point-slope form with point \((2, -3)\):
📌 ÷ 11 ≈ 13.909 → no
📌 So the smallest multiple of 11 in [100,199] divisible by 9 is 198.

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