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Home » P(k; n, p) = \binomnk p^k (1-p)^n-k - AMAZONAWS

P(k; n, p) = \binomnk p^k (1-p)^n-k - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
P(k; n, p) = \binom{n}{k} p^k (1-p)^{n-k}

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