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📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 Similarly, 37 + 2 = 39 â better.
📌 But more precisely: for a given $ B $, if there exists $ D \in [100, 199] $, $ D \equiv 0 \pmod{9} $, and $ 9 \mid D $, such that $ B \mid D $, then $ D = B \cdot k $, so $ B $ must be a divisor of some multiple of 9 in that interval.
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