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\[ C'(t) = \frack(1 - t^2)(t^2 + 1)^2 \] - AMAZONAWS
\[ C'(t) = \frack(1 - t^2)(t^2 + 1)^2 \] - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 But more precisely: for a given $ B $, if there exists $ D \in [100, 199] $, $ D \equiv 0 \pmod{9} $, and $ 9 \mid D $, such that $ B \mid D $, then $ D = B \cdot k $, so $ B $ must be a divisor of some multiple of 9 in that interval.
📌 ÷ 11 = 18 â yes!
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![\[ C'(t) = \frac{k(1 - t^2)}{(t^2 + 1)^2} \]](https://soloferat.biz.id/images/-ct--frack1---t2t2--12-.jpg)
