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Home » n = \frac{-b \pm \sqrtb^2 - 4ac}2a \\ - AMAZONAWS

n = \frac{-b \pm \sqrtb^2 - 4ac}2a \\ - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \\$

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So \( x^2 = 0 \), hence \( x = 0 \), \( y = \pm8 \).

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