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Home » = \frac{(\sqrt3 + 1)^2}{(\sqrt3 - 1)(\sqrt3 + 1)} = \frac{3 + 2\sqrt3 + 1}3 - 1 = \frac{4 + 2\sqrt3}2 = 2 + \sqrt3 - AMAZONAWS

= \frac{(\sqrt3 + 1)^2}{(\sqrt3 - 1)(\sqrt3 + 1)} = \frac{3 + 2\sqrt3 + 1}3 - 1 = \frac{4 + 2\sqrt3}2 = 2 + \sqrt3 - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
= \frac{(\sqrt{3} + 1)^2}{(\sqrt{3} - 1)(\sqrt{3} + 1)} = \frac{3 + 2\sqrt{3} + 1}{3 - 1} = \frac{4 + 2\sqrt{3}}{2} = 2 + \sqrt{3}

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📌 x^2 + 1 = x^2 + \frac{x^2}{x^2} = x^2 + 1 \Rightarrow \text{Try direct substitution}

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