\[ x = -\frac\tan\theta{2\left(-\fracg2v_0^2\cos^2\theta\right)} = \fracv_0^2\sin\theta\cos\thetag. \] - AMAZONAWS 📅 March 11, 2026 👤 scraface Mar 11, 2026
![\[ x = -\frac{\tan\theta}{2\left(-\frac{g}{2v_0^2\cos^2\theta}\right)} = \frac{v_0^2\sin\theta\cos\theta}{g}. \]](https://soloferat.biz.id/images/-x---fractantheta2left-fracg2v02cos2thetaright--fracv02sinthetacosthetag-.jpg)
