z = \omega^1/3 = e^2\pi i / 9,\ e^2\pi i (1+3)/9 = e^8\pi i / 9,\ e^2\pi i (1+6)/9 = e^14\pi i / 9 \quad \text(mod 2\pi). - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$z = \omega^{1/3} = e^{2\pi i / 9},\ e^{2\pi i (1+3)/9} = e^{8\pi i / 9},\ e^{2\pi i (1+6)/9} = e^{14\pi i / 9} \quad \text{(mod } 2\pi).$