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Home » Thus, \(\cos 60^\circ\) is \(\boxed{\frac12}\).Question: Find $\tan \theta$ where $\theta$ is the angle between the line of sight from a weather balloon at $(2, 3)$ to a cloud at $(5, 11)$ and the horizontal axis. - AMAZONAWS

Thus, \(\cos 60^\circ\) is \(\boxed{\frac12}\).Question: Find $\tan \theta$ where $\theta$ is the angle between the line of sight from a weather balloon at $(2, 3)$ to a cloud at $(5, 11)$ and the horizontal axis. - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
Thus, \(\cos 60^\circ\) is \(\boxed{\frac{1}{2}}\).Question: Find $\tan \theta$ where $\theta$ is the angle between the line of sight from a weather balloon at $(2, 3)$ to a cloud at $(5, 11)$ and the horizontal axis.

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