Then, $ a^2 = 1 $ and $ d^2 = 1 $. So, $ a = \pm 1 $ and $ d = \pm 1 $. The diagonal matrices $ eginpmatrix \pm 1 & 0 \ 0 & \pm 1 \endpmatrix $ satisfy $ T^2 = I $. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$Then, $ a^2 = 1 $ and $ d^2 = 1 $. So, $ a = \pm 1 $ and $ d = \pm 1 $. The diagonal matrices $ egin{pmatrix} \pm 1 & 0 \ 0 & \pm 1 \end{pmatrix} $ satisfy $ T^2 = I $.$

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