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Home » The divisors of 60 are of the form \( 2^a \cdot 3^b \cdot 5^c \) where \( 0 \leq a \leq 2 \), \( 0 \leq b \leq 1 \), \( 0 \leq c \leq 1 \). - AMAZONAWS

The divisors of 60 are of the form \( 2^a \cdot 3^b \cdot 5^c \) where \( 0 \leq a \leq 2 \), \( 0 \leq b \leq 1 \), \( 0 \leq c \leq 1 \). - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
The divisors of 60 are of the form \( 2^a \cdot 3^b \cdot 5^c \) where \( 0 \leq a \leq 2 \), \( 0 \leq b \leq 1 \), \( 0 \leq c \leq 1 \).

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📌 + largeur = 20
📌 Question:** An electrical engineer analyzes the magnetic flux through a coil whose area vector \( \vec{A} \) rotates in the \( xy \)-plane. If \( \vec{A}(t) = A_0 \cos(\omega t) \hat{\mathbf{x}} + A_0 \sin(\omega t) \hat{\mathbf{y}} \) and the magnetic field is \( \vec{B} = B_0 \hat{\mathbf{z}} \), compute the time average of the magnetic flux \( \Phi_B = \vec{B} \cdot \vec{A}(t) \) over one period.
📌 Thus, \( \Phi_B(t) = 0 \) for all \( t \). The time average over one period \( T = \frac{2\pi}{\omega} \) is:
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