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Home » Number of distinct permutations of A,A,B,C: $ \frac4!2! = 12 $ - AMAZONAWS

Number of distinct permutations of A,A,B,C: $ \frac4!2! = 12 $ - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
Number of distinct permutations of {A,A,B,C}: $ \frac{4!}{2!} = 12 $

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  • S(7,3) = 3 \cdot 90 + 31 = 270 + 31 = 301.
  • with $ a_1 = 2 $ (E, J), $ a_2 = 3 $ (EE, EJ, JE) — JJ is invalid.
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