\langle \Phi_B \rangle = \frac1T \int_0^T \Phi_B(t) \, dt = \frac1T \int_0^T 0 \, dt = 0 - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$\langle \Phi_B \rangle = \frac{1}{T} \int_0^T \Phi_B(t) \, dt = \frac{1}{T} \int_0^T 0 \, dt = 0$