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Home » We evaluate $ (x^2 + x + 1)^3 $ at $ x = \omega $: - AMAZONAWS

We evaluate $ (x^2 + x + 1)^3 $ at $ x = \omega $: - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$We evaluate $ (x^2 + x + 1)^3 $ at $ x = \omega $:$

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We use the recurrence: $S(n,k) = k \cdot S(n-1,k) + S(n-1,k-1)$

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