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Home » Let $ x_1 + x_2 + x_3 + x_4 = 6 $, where $ x_i \geq 1 $. - AMAZONAWS

Let $ x_1 + x_2 + x_3 + x_4 = 6 $, where $ x_i \geq 1 $. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$Let $ x_1 + x_2 + x_3 + x_4 = 6 $, where $ x_i \geq 1 $.$

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Probability for two primes: $\left(\frac{1}{2}\right)^2 = \frac{1}{4}$
Thus, $S(5,3) = 25$
$S(4,2) = 2^2 - 1 = 7$? No — standard recurrence:

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