We are given that the angle between $ z_1 $ and $ z_2 $ is $ 60^\circ $, which corresponds to the smallest positive argument of $ z_1 \overlinez_2 $. Since both are on the unit circle, $ |z_1| = |z_2| = 1 $, and - AMAZONAWS 📅 March 11, 2026 👤 scraface Mar 11, 2026