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Home » Total amount: \(2000 \times (1 + 0.005)^24 = 2000 \times 1.12716 = 2254.32\) - AMAZONAWS

Total amount: \(2000 \times (1 + 0.005)^24 = 2000 \times 1.12716 = 2254.32\) - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
Total amount: \(2000 \times (1 + 0.005)^{24} = 2000 \times 1.12716 = 2254.32\)

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📌 Solution: The perimeter of a rectangle is given by $ P = 2(l + w) $, where $ l $ is length and $ w $ is width. Given $ 2(l + w) = 80 $, we simplify to $ l + w = 40 $. The area $ A = lw $. Express $ w = 40 - l $, so $ A = l(40 - l) = 40l - l^2 $. This quadratic equation opens downward, and its maximum occurs at the vertex $ l = \frac{-b}{2a} = \frac{-40}{-2} = 20 $. Substituting $ l = 20 $, $ w = 20 $, so $ A = 20 \times 20 = 400 $. The maximum area is $\boxed{400}$.
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