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Substituting \( n = 8 \) and \( r = 3 \): - AMAZONAWS
Substituting \( n = 8 \) and \( r = 3 \): - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 So $x^2 = 144(k^2 + 1) = (12)^2(k^2 + 1)$, hence $x = 12\sqrt{k^2 + 1}$. For $x$ to be integer, $k^2 + 1$ must be a perfect square. Let $k^2 + 1 = m^2$, so:
📌 $2^9 = 12$
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