P'(t) = -1000 \cdot \frac{-4.5e^-0.5t}{(1 + 9e^-0.5t)^2} = \frac{4500e^-0.5t}{(1 + 9e^-0.5t)^2}. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$P'(t) = -1000 \cdot \frac{-4.5e^{-0.5t}}{(1 + 9e^{-0.5t})^2} = \frac{4500e^{-0.5t}}{(1 + 9e^{-0.5t})^2}.$