In fact, since $8 = 2^3$, for $n^3 \equiv 0 \pmod8$, $n$ must be divisible by 2. Try small even values: - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$In fact, since $8 = 2^3$, for $n^3 \equiv 0 \pmod{8}$, $n$ must be divisible by 2. Try small even values:$