ight)^2 $ term has same denominator $ rac649 $, and $ y^2 $ has $ rac1929 $, so it's elliptical in $ x/z $-plane. But more precisely, since the equation resembles $ racx^2 + y^2a^2 + rac(z - z_0)^2b^2 = 1 $, with $ a - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$ight)^2 $ term has same denominator $ rac{64}{9} $, and $ y^2 $ has $ rac{192}{9} $, so it's **elliptical** in $ x/z $-plane. But more precisely, since the equation resembles $ rac{x^2 + y^2}{a^2} + rac{(z - z_0)^2}{b^2} = 1 $, with $ a$