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Home » \frac{a + \frac12 \cdot \frac{2a\sqrt7}3}{a - \frac32 \cdot \frac{2a\sqrt7}3} = \frac{a + \frac{a\sqrt7}3}{a - a\sqrt7} = \frac{1 + \frac{\sqrt7}3}{1 - \sqrt7} = \frac{\frac{3 + \sqrt7}3}{1 - \sqrt7} = \frac{3 + \sqrt7}{3(1 - \sqrt7)}. - AMAZONAWS

\frac{a + \frac12 \cdot \frac{2a\sqrt7}3}{a - \frac32 \cdot \frac{2a\sqrt7}3} = \frac{a + \frac{a\sqrt7}3}{a - a\sqrt7} = \frac{1 + \frac{\sqrt7}3}{1 - \sqrt7} = \frac{\frac{3 + \sqrt7}3}{1 - \sqrt7} = \frac{3 + \sqrt7}{3(1 - \sqrt7)}. - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
\frac{a + \frac{1}{2} \cdot \frac{2a\sqrt{7}}{3}}{a - \frac{3}{2} \cdot \frac{2a\sqrt{7}}{3}} = \frac{a + \frac{a\sqrt{7}}{3}}{a - a\sqrt{7}} = \frac{1 + \frac{\sqrt{7}}{3}}{1 - \sqrt{7}} = \frac{\frac{3 + \sqrt{7}}{3}}{1 - \sqrt{7}} = \frac{3 + \sqrt{7}}{3(1 - \sqrt{7})}.

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