e^-0.5t = \frac19 \Rightarrow -0.5t = \ln\left(\frac19\right) = -\ln 9 \Rightarrow t = 2\ln 9. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$e^{-0.5t} = \frac{1}{9} \Rightarrow -0.5t = \ln\left(\frac{1}{9}\right) = -\ln 9 \Rightarrow t = 2\ln 9.$