\cos(2lpha - 90^\circ) = \cos(90^\circ - 2lpha) = \sin(2lpha) \quad extonly if adjusting sign properly. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$\cos(2lpha - 90^\circ) = \cos(90^\circ - 2lpha) = \sin(2lpha) \quad ext{only if adjusting sign properly}.$