\( \left[ \frac25 h^5/2 \right]_12^h = -\frac28.825\pi \cdot 10 = -\frac28825\pi \) - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
![\( \left[ \frac{2}{5} h^{5/2} \right]_{12}^{h} = -\frac{28.8}{25\pi} \cdot 10 = -\frac{288}{25\pi} \)](https://soloferat.biz.id/images/-left-frac25-h52-right12h---frac28825pi-cdot-10---frac28825pi-.jpg)
\( \left[ \frac25 h^5/2 \right]_12^h = -\frac28.825\pi \cdot 10 = -\frac28825\pi \) - AMAZONAWS
Mar 11, 2026
