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#### 58.5 - AMAZONAWS

Exploring #### 58.5: Unlocking the Significance Behind This Key Number

📅 March 11, 2026 👤 scraface

Mar 11, 2026

#### 58.5

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📌 So $x^2 = 144(k^2 + 1) = (12)^2(k^2 + 1)$, hence $x = 12\sqrt{k^2 + 1}$. For $x$ to be integer, $k^2 + 1$ must be a perfect square. Let $k^2 + 1 = m^2$, so:

📌 Now compute $\gcd(72, 432)$.

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