Then \( racx+yx-y = rac{\sqrt5+1}{\sqrt5-1} = rac{3+\sqrt5}2 \), valid. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$Then \( rac{x+y}{x-y} = rac{\sqrt{5}+1}{\sqrt{5}-1} = rac{3+\sqrt{5}}{2} \), valid.$