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Home » So $ A(t) = -3t^2 + 16t + 12 $. The maximum occurs at $ t = -\fracq2p = -\frac16{2(-3 - AMAZONAWS

So $ A(t) = -3t^2 + 16t + 12 $. The maximum occurs at $ t = -\fracq2p = -\frac16{2(-3 - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
So $ A(t) = -3t^2 + 16t + 12 $. The maximum occurs at $ t = -\frac{q}{2p} = -\frac{16}{2(-3

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