\[ b^3 + c^3 = (b + c)(b^2 - bc + c^2) = 12 \cdot 39 = 468 \] - AMAZONAWS 📅 March 11, 2026 👤 scraface Mar 11, 2026
![\[ b^3 + c^3 = (b + c)(b^2 - bc + c^2) = 12 \cdot 39 = 468 \]](https://soloferat.biz.id/images/-b3--c3--b--cb2---bc--c2--12-cdot-39--468-.jpg)
