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20 Dec. 2012

Find numbers that divide evenly,search cell phone number by name,reverse phone lookup cell - Try Out

The theme to this announcement is "octave." The eight Hebrew letters around the outside of the 8-pointed star, are actually numbers.
Add up all the numbers in the star (Chet=60 + Waw or Vav=80 + Daleth=100 + Beth=300 + Sadhe=5 + Gimel=200 + Yod=40 + Samech=8 + Ayin=7) to get 800. In the picture, if you add together all the squared numbers for the weapons that line up vertically in the center (12^2=144 + 4^2=16 + 8^2=64 + 10^=100) you get 324 decimal that equals to 144 (12x12) or (8x18) hex. Keeping in tune with the "octave" theme of this announcement, make a new chart (see below) with the numbers from the above chart that are evenly divisible by eight. Notice that the above chart starts with the number eight at the top right of the triangle, and ends with 88 at the bottom of the triangle. The above chart, beginning with numbers 1 to 11 for the first row, resolves down to the number 6144. Once again we derive at the number 12, and we also see how the number 8 relates harmoniously with 12. Notice that the above chart of seven rows is the next group of numbers from the previous chart of eleven rows that can be evenly divided by eight. Finally, the bottom number (96) in the previous chart can be evenly divided by eight to get twelve. 420 is the smallest number that can be divided evenly by all the natural numbers from 1 to 7.
Yes, the number formed from its last two digits, 20, is divisible by 4, so 120 is divisible by 4, and 4 x 30 = 120. From this thinking process we conclude that the factor pairs of 120 are 1 x 120, 2 x 60, 3 x 40, 4 x 30, 5 x 24, 6 x 20, 8 x 15, and 10 x 12. When 120 is a clue in the FIND THE FACTORS 1 – 12 puzzles, use 10 and 12 as the factors.

When 33 is a clue in the FIND THE FACTORS 1 – 12 puzzles, always use 3 and 11 as the factors. Probably you noticed or a teacher taught you the easy way to remember what 9 times a numbers from one to ten is just as the chart illustrates. 2 + 4 + 3 = 9, which is divisible by both 3 and 9, so, yes, 243 is divisible by both 3 and 9.
When you add up the digits of a number until you have only one digit left, if that digit is not 9, then that number is the remainder you would get if you did the actual division!
All of these problems demonstrate that if you add the digits of a number until you are left with a single digit, if that digit is 3, 6, or 9, then the original number is divisible by 3.
The last problem demonstrates that if you divide that single digit by 3, the remainder will be the same if you divided the original number by 3. Even though 2014 hasn’t even started, I am going to predict the factors of 2014, and I am absolutely positive that my predictions will be 100% correct. Most people expect the number One to be a positive factor every single year, and it will not let us down in 2014. All you have to do to solve one of the puzzles is write the numbers 1 – 12 in the top row and again in the first column so that those numbers are the factors of the given clues. At the top of this post is a page titled How to Find the Factors, and it gives hints to solve the puzzles. When 6 is a clue in the FIND THE FACTORS  puzzle, the pair that will work for that particular puzzle might be 1 x 6, or it might be 2 x 3. In this post I talk about factor trees, and I describe how to use the cake method to find the factors of a number. 720 isn’t even that big of a number, but gathering all of the prime numbers from the factor tree and putting them in numerical order would be like picking up a bunch of scattered leaves.

If they are different, find a common denominator for the two x4 7 8 numbers. This is called a divisibility trick because it is a way to find out if a number is divisible by 9 without actually dividing by 9. The puzzles for today’s post could also be called factor trees because you have to factor the clues to find the solution, and the puzzles are shaped like evergreen trees in whole or in part. Today we have puzzles that look like Christmas trees, garland, lights, or blocks and a bright star for the very top. Since she was not a factor at all in 2013, I am confident that she will get her act together again in 2014 and become a factor once more.
Every time I have been given an assignment to become acquainted with them, I have approached that assignment with enthusiasm and determination. Of course, many of those factors were so obscure that most people never gave them a second thought all year long. I predict that 2014 will have three prime factors, namely 2, 19, and 53, as illustrated in the following graphic.
When those two or more factors are all prime factors, it is called the prime factorization of the number. A composite number always has more than two factors. Notice that some of the prime factors of 720 (2,2,2,2,3,3,5) are not as easy to see as others on the factor tree.

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