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In this section you will participate in {{ C.NUM_ROUNDS_PART_B }} independent decision-making problems that share a common form.
In each round you will be asked to allocate points between two accounts: BLUE
and RED. At the start of each round the computer will randomly select your
budget and prices of points that can be allocated to the BLUE and
RED accounts. You will be allowed to allocate any number of points to the
BLUE and RED accounts as long as the total expenditure
is equal to the budget. That is, the total cost of points allocated to both accounts, given the prices, must
be equal to your budget. Equivalenty,
it must be that
Suppose the computer randomly selects your budget to be 60. The price of points assigned to the BLUE account is 3/2 and the price of the points assigned to the RED account is 1. Therefore, allocating 0 points to the BLUE account and 60 points to the RED exhausts the budget, since 60 = 3/2 · 0 + 1 · 60. Similarly, allocating 40 points to the BLUE account and 0 points to the RED exhausts the budget as well, since 60 = 3/2 · 40 + 1 · 0. So does the allocation of 20 points to the BLUE account and 30 points to the RED, and so on.
Since the price of the points allocated to the RED account is always equal to 1, the price of BLUE points determines how many points you can add to the RED account if you subtract one point from the BLUE account.
Suppose that the price of points assigned to the BLUE account is 3/2 and the price of the points assigned to the RED account is 1. Then, subtracting 1 point from the BLUE account allows you to add 3/2 points to the RED account. Similarly, subtracting 2 points from the BLUE account allows you to add 3 points to the RED account, and so on.
Press 'Next' to continue with the instructions to Section B1.
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