{{ block title }} Introduction {{ endblock }} {{ block content }}
This is an experiment in the economics of decision making. In this experiment, we simulate a procedure to allocate students to schools. The procedure, payment rules, and student allocation method are described below. Do not communicate with each other during the experiment. If you have questions at any point during the experiment, write them in a chat.
Procedure
Allocation Method
An Example
We go through a simple example to illustrate how the allocation method works.
Students and Schools: In this example, there are six students, 1-6, and four schools, Clair, Erie, Huron and Ontario.
Student ID: 1,2,3,4,5,6
Schools: Clair, Erie, Huron, Ontario
Slots and Residents: There are two slots each at Clair and Erie, and one slot each at Huron and Ontario. Residents of districts are indicated in the table below.
Tentative assignments: Students are tentatively assigned slots at their district schools.

Lottery: The lottery produces the following order. 1-2-3-4-5-6
Submitted School Rankings: The students submit the following school rankings:
|
|
1st choice |
2nd choice |
3rd choice |
Last choice |
|
Student 1 |
Erie |
Ontario |
Clair |
Huron |
|
Student 2 |
Erie |
Clair |
Ontario |
Huron |
|
Student 3 |
Huron |
Erie |
Clair |
Ontario |
|
Student 4 |
Erie |
Ontario |
Clair |
Huron |
|
Student 5 |
Erie |
Clair |
Huron |
Ontario |
|
Student 6 |
Huron |
Ontario |
Erie |
Clair |
This allocation method consists of the following steps:
|
|
Queue |
Available Slots |
The top student in the queue applies to a school. |
At the end of the step |
|
Step 1 |
1-2-3-4-5-6 |
Clair Clair Ontario |
1 applies to her last choice Huron, which is tentatively assigned to 5. |
5 comes to the top |
|
Step 2 |
5-1-2-3-4-6 |
Clair Clair Ontario |
5 applies to her last choice Ontario, which is tentatively assigned to 6. |
6 comes to the top. |
|
Step 3 |
6-5-1-2-3-4 |
Clair Clair Ontario |
6 applies to her last choice Clair, which is tentatively assigned to 1 and 2. |
1 comes to the top. |
|
Step 4 |
1-6-5-2-3-4 |
Clair Clair Ontario |
A cycle happens in the last 3 steps. |
1 gets a slot at Huron. 5 gets a slot at Ontario. 6 gets a slot at Clair. |
|
Step 5 |
2-3-4 |
Clair |
2 applies to her 2nd choice Clair, because her last and 3rd choices (Huron and Ontario) are no longer available |
2 gets a slot at Clair, because she is a resident in Clair |
|
Step 6 |
3-4 |
Erie Erie |
3 applies to Erie which is still available. |
3 gets a slot at Erie, because he is a resident in Erie. |
|
Step 7 |
4 |
Erie |
4 applies to Erie. |
4 gets a slot at Erie, because she is a resident in Erie. |
Final assignment: Based on this method, the final allocations are
|
Student |
1 |
2 |
3 |
4 |
5 |
7 |
|
School |
Huron |
Clair |
Erie |
Erie |
Ontario |
Clair |
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