We are given that $ \fracdVdt = k \sin \theta $, and $ \theta = 60^\circ $, so $ \sin \theta = \frac{\sqrt3}2 $. Substituting: - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$We are given that $ \frac{dV}{dt} = k \sin \theta $, and $ \theta = 60^\circ $, so $ \sin \theta = \frac{\sqrt{3}}{2} $. Substituting:$