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under the constraint $ x + y + z = 3 $. - AMAZONAWS
under the constraint $ x + y + z = 3 $. - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 Contradiction! So no solution exists unless the cross product is orthogonal to \(\mathbf{a}\), which \(egin{pmatrix} 0 \ 0 \ 5 \end{pmatrix} \cdot egin{pmatrix} 1 \ 2 \ 3 \end{pmatrix} = 15
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