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Home » Solution: The ratio of emissions is $4:7:9$. Let the common multiplier be $x$. Then the second borough emitted $7x = 147$ metric tons. Solving for $x$: - AMAZONAWS

Solution: The ratio of emissions is $4:7:9$. Let the common multiplier be $x$. Then the second borough emitted $7x = 147$ metric tons. Solving for $x$: - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
Solution: The ratio of emissions is $4:7:9$. Let the common multiplier be $x$. Then the second borough emitted $7x = 147$ metric tons. Solving for $x$:

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  • × 39 = 6.1051×30 + 6.1051×9 = 183
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