\int_0^45 (60 - (B + 15))\, dB = \int_0^45 (45 - B)\, dB = \left[45B - \frac12B^2\right]_0^45 = 45 \cdot 45 - \frac12 \cdot 45^2 = 2025 - \frac20252 = \frac20252 = 1012.5 - AMAZONAWS 📅 March 11, 2026 👤 scraface Mar 11, 2026
![\int_{0}^{45} (60 - (B + 15))\, dB = \int_{0}^{45} (45 - B)\, dB = \left[45B - \frac{1}{2}B^2\right]_0^{45} = 45 \cdot 45 - \frac{1}{2} \cdot 45^2 = 2025 - \frac{2025}{2} = \frac{2025}{2} = 1012.5](https://soloferat.biz.id/images/int045-60---b--15-db--int045-45---b-db--left45b---frac12b2right045--45-cdot-45---frac12-cdot-452--2025---frac20252--frac20252--10125.jpg)
