Solution: The volume of the cylinder is $ V_{\textcyl} = \pi r^2 (6r) = 6\pi r^3 $. The volume of the cone is $ V_{\textcone} = \frac13 \pi (2r)^2 (3r) = \frac13 \pi (4r^2)(3r) = 4\pi r^3 $. The ratio is: - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$Solution: The volume of the cylinder is $ V_{\text{cyl}} = \pi r^2 (6r) = 6\pi r^3 $. The volume of the cone is $ V_{\text{cone}} = \frac{1}{3} \pi (2r)^2 (3r) = \frac{1}{3} \pi (4r^2)(3r) = 4\pi r^3 $. The ratio is:$

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