Solution: The tangent of $ 45^\circ $ is defined as $ \frac\sin 45^\circ\cos 45^\circ = \frac{\frac{\sqrt2}2}{\frac{\sqrt2}2} = 1 $. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$Solution: The tangent of $ 45^\circ $ is defined as $ \frac{\sin 45^\circ}{\cos 45^\circ} = \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1 $.$